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The Denominator of $ L(A,1)/\Omega _A$

In this section, we prove a result about the denominator of the rational number $ L(A,1)/\Omega _A$ and compare it to what is predicted by the Birch and Swinnerton-Dyer conjecture.

Proposition 4.6   Let $ z$ be the point in $ J_0(N)(\mathbf{Q})$ defined by the degree 0 divisor $ (0)-(\infty)$ on $ X_0(N)$, and let $ n = n_f$ be the order of the image of $ z$ in $ A(\mathbf{Q})$. Then the denominator of $ c_\infty\cdot c_A\cdot L(A,1)/\Omega_A $ divides $ n$.

Proof. Let $ x$ be the image of $ z$ in $ A(\mathbf{Q})$, and set $ I=\Ann(x)\subset\mathbf{T}$. Since $ f$ is a newform, the Hecke operators $ T_p$, for $ p\mid{}N$, act as 0 or $ \pm 1$ on $ A(\mathbf{Q})$ (see, e.g., [DI95, §6]). If $ p\nmid N$, then a standard calculation (see, e.g., [Cre97, §2.8]) shows that $ T_p(x) = (p+1)x$. There is an injection $ \mathbf{T}/I\hookrightarrow C=\mathbf{Z}{}x$ sending $ T_p$ to $ T_p(x)$, where $ C$ is the order-$ n$ cyclic subgroup of $ A(\mathbf{Q})$ generated by $ x$. With notation as in the proof of Theorem 4.5, we have
$\displaystyle \frac{L(A,1)}{\Omega_A}\cdot c_\infty\cdot c_A$ $\displaystyle =$ $\displaystyle [\Phi(H)^+:\Phi(\mathbf{T}{}e)]$  
  $\displaystyle =$ $\displaystyle [\Phi(H)^+:\Phi(I e)]\cdot [\Phi(I e):\Phi(\mathbf{T}{}e)]$  
  $\displaystyle =$ $\displaystyle [\Phi(H)^+:I\Phi(e)]\cdot [I\Phi(e):\mathbf{T}{}\Phi(e)]$  
  $\displaystyle =$ $\displaystyle \frac{[\Phi(H)^+:I\Phi(e)]}{[\mathbf{T}{}\Phi(e):I\Phi(e)]} \in \frac{1}{n}\mathbf{Z}.$  

The final inclusion follows from two observations. First, the index $ [\Phi(H)^+:I\Phi(e)]$ is an integer because $ I$ is exactly the ideal of elements of $ \mathbf{T}$ that send $ x=\Phi(e)$ into $ \Phi(H)$, and $ x\in \Phi(H\otimes \mathbf{Q})^+$. Second, there is a surjective map

$\displaystyle \mathbf{T}/I \rightarrow \frac{\mathbf{T}{}\Phi(e)}{I P(e)}$

sending $ t$ to $ t \Phi(e)$, so $ [\mathbf{T}{}\Phi(e):IP(e)]$ divides $ n=\char93 C=\char93 (\mathbf{T}/I)$. $ \qedsymbol$

Conjecture 2.2 predicts that

$\displaystyle \char93 A(\mathbf{Q})\cdot \char93 A^{\vee}(\mathbf{Q}) \cdot \fr...
...\fontseries{m}\fontshape{n}\selectfont Sh}}}(A)\cdot \prod c_p \in \mathbf{Z},
$

and since $ n\mid \char93 A(\mathbf{Q})$, Proposition 4.6 implies that

$\displaystyle c_\infty \cdot c_A \cdot \char93 A(\mathbf{Q}) \cdot \frac{L(A,1)}{\Omega_A} \in \mathbf{Z}.
$

Since $ c_\infty$ is a power of $ 2$, and $ c_A$ is conjecturally one (if $ N$ is prime, then it is known to be a power of $ 2$), Proposition 4.6 provides theoretical evidence for Conjecture 2.2, and also reflects a surprising amount of cancellation between $ \prod c_p$ and $ \char93 A^{\vee}(\mathbf{Q})$.


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Next: Tables Up: The Quotient Previous: A Formula for
William A Stein 2002-02-02